Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

Energy order of sub-shell decided by $\left(\mathrm{n}+\mathrm{l}\right)$ value.

Greater the $\left(\mathrm{n}+\mathrm{l}\right)$ value of a sub-shell greater is its energy.

If two sub-shells have same $\left(\mathrm{n}+\mathrm{l}\right)$ values the orbital with greater principal quantum number has greater energy

$\mathrm{A}\Rightarrow 3 \mathrm{d}\Rightarrow \left(\mathrm{n}+\mathrm{l}\right)=3+2=5$

$\mathrm{B}\Rightarrow 4\mathrm{p}\Rightarrow \mathrm{n}+\mathrm{l}=4+1=5$

$\mathrm{C}\Rightarrow 4 \mathrm{d}\Rightarrow \mathrm{n}+\mathrm{l}=4+2=6$

$\mathrm{D}\Rightarrow 3\mathrm{s}\Rightarrow \left(\mathrm{n}+\mathrm{l}\right)=3+0=3$

$\mathrm{D}<\mathrm{A}<\mathrm{B}<\mathrm{C}$