Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryMiscellaneous/MixedMedium2 min

ChemistryMediumsingle choice

Passage / Comprehension

1 L of aqueous solutions of CaI₂ is electrolyzed. After electrolysis the gas evolved at anode required

250 mL, 2M hypo solution (Na₂S₂O₃)

What is the pH of the solution after electrolysis (assume no hydrolysis of any ion) :

Answer:

Solution:

$2 H_{2} O + 2 e^{-} \to H_{2} + 2 OH^{-}$

$n_{O H^{-}} = \frac{1}{2}$

$[O H^{-}] = 0.5$

$pO H = 1 - lo g 5 = 0.3$

$p H = 13.7$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Miscellaneous/Mixed

⏱ 2m

Loading discussions...