Pure water is saturated with pure solid AgCl , a silver electrode is placed in the solution and the potential is measured against normal calomel electrode at 2 5 ∘ C . The experiment is then repeated

Question

Pure water is saturated with pure solid AgCl , a silver electrode is placed in the solution and the potential is measured against normal calomel electrode at 2 5 ∘ C . The experiment is then repeated with a saturated solution of AgI . If the difference in potential in the two cases is 0 ⋅ 177 V . What is the ratio of solubilities of AgCl and AgI at the temperature of the experiment?

TestHub · Accepted Answer

Ag + +e - →Ag (from AgCl) E 1 ​ = E 1 ∘ ​ − 1 0.0591 ​ lo g C 1 ​ 1 ​ Where C 1 ​ is the concentration of Ag⁺ in a saturated AgCl solution. E 2 ​ = E 2 ∘ ​ − 1 0.0591 ​ lo g C 2 ​ 1 ​ Where C 2 ​ is the concentration of Ag⁺ in a saturated AgI solution. E 1 ​ − E 2 ​ = 0.177 = + 0.059 lo g ​ C 2 ​ C 1 ​ ​ lo g ( C 2 ​ C 1 ​ ​ ) = 3 Therefore, C 2 ​ C 1 ​ ​ = 1 0 3 .

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