Calculate value of E ° C e 4 + / C e 3 + . If E ° c e l l for the cell reaction, 2 C e 4 + + C o → 2 C e 3 + + C o 2 + is 1.89 V. If E ° C o / C o 2 + = - 0.28 V

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ChemistryElectrochemistryMiscellaneous/MixedEasy2 minPYQ_2020

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Calculate value of $E °_{C e^{4 +} / C e^{3 +}}$ . If $E °_{c e l l}$ for the cell reaction, $2 C e^{4 +} + C o \to 2 C e^{3 +} + C o^{2 +}$ is 1.89 V. If $E °_{C o / C o^{2 +}}$ $= - 0.28 V$

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Answer:

Solution:

In this cell $C o$ is oxidised and it acts as anode and Ce acts as cathode.

$E_{C e l l}^{0} = E_{C a t h o d e}^{0} - E_{A n o d e}^{0} = 1.89 = E_{C e l l}^{0} - (- 0.28)$

$E_{C e l l}^{0} = 1.89 - 0.28 = 1.61$ Volts.

Stream:NTA_ABHYASSubject:ChemistryTopic:ElectrochemistrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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