Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 min

ChemistryMediumsingle choice

The value of "x" is

Answer:

Solution:

$B r O_{3}^{-} + 3 H_{2} O + 6 e^{-} \to B r^{-} + 6 O H^{-}$ ΔG₁⁰ =?.........................(1)

$B r O_{3}^{-} + 2 H_{2} O + 4 e^{-} \to B r O^{-} + 4 O H^{-}$ ΔG₂⁰ = -4F(0.54).............(2)

$B r O_{-} + H_{2} O + 2 e^{-} \to B r^{-} + 2 O H^{-}$ ΔG₃⁰ = -2F(0.17)...............(3)

Solving the above 3 equations by

(2) + (3) = (1)

ΔG₁⁰ = -2.5VF

E = 0.417V

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

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