Chemistry - Electrochemistry Question with Solution | TestHub

$∆{\mathrm{\text{G}}}^{\mathrm{\text{o}}}=-\mathrm{\text{n}}\mathrm{\text{F}}{\mathrm{\text{E}}}^{\mathrm{\text{o}}}$

if${\mathrm{\text{E}}}^{\mathrm{\text{o}}}=\mathrm{\text{p}}\mathrm{\text{o}}\mathrm{\text{s}}\mathrm{\text{i}}\mathrm{\text{t}}\mathrm{\text{i}}\mathrm{\text{v}}\mathrm{\text{e}};$then$∆{\mathrm{\text{G}}}^{\mathrm{\text{o}}}=\mathrm{\text{n}}\mathrm{\text{e}}\mathrm{\text{g}}\mathrm{\text{a}}\mathrm{\text{t}}\mathrm{\text{i}}\mathrm{\text{v}}\mathrm{\text{e}}$,

For those, conversions whose${\text{E}}^{\text{o}}$values are more positive are more favourable.
As we can see from then electrode potential data, that reduction of${\mathrm{Al}}^{+}$is spontaneous, but reduction of${\mathrm{Tl}}^{+}$is not. So, we can conclude from this that$\text{T}{\text{l}}^{+}$is more stable than$\text{A}{\text{l}}^{+}$