Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsHard2 minQB
ChemistryHardmatching list

Match Column I with Column II. Select the correct mapping. Standard reduction potentials: E°(F₂/F⁻) = +2.87 V; E°(Li⁺/Li) = −3.5 V; E°(Au³⁺/Au) = +1.4 V; E°(Br₂/Br⁻) = +1.09 V.

Column I

Column II

(i) F₂

(a) metal strongest reducing agent

(ii) Li

(b) metal ion weakest oxidising agent

(iii) Au³⁺

(c) non-metal best oxidising agent

(iv) Br⁻

(d) unreactive metal

(v) Au

(e) anion oxidised by Au³⁺

(vi) Li⁺

(f) anion weakest reducing agent

(vii) F⁻

(g) metal ion oxidising agent

 

Options:

Answer:
A
Solution:

F⁻ is the weakest reducing anion, so (vii) maps only to (f). The source key also gives (g), a metal-ion description, to F⁻; that erroneous duplicate is removed in this corrected conversion.

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells
⏱ 2mℹ️ Source: QB

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