Three faradays of charge is passed through an aqueous solution of $NaClO_{3}$ when $NaClO_{4}$ is formed according to the reaction,

$NaClO_{3} + H_{2} O ⟶ NaClO_{4} + H_{2}$
How many moles of $NaClO_{4}$ will be formed during the electrolysis?

Question

Three faradays of charge is passed through an aqueous solution of $NaClO_{3}$ when $NaClO_{4}$ is formed according to the reaction,

$NaClO_{3} + H_{2} O ⟶ NaClO_{4} + H_{2}$

How many moles of $NaClO_{4}$ will be formed during the electrolysis?

TestHub · Accepted Answer

Two faradays of charge is required to convert one mole of NaClO₃ to NaClO₄. When 3 faradays of charge is passed through an aqueous solution of NaClO₃, 1.5 moles of NaClO₄ will be formed.

Chemistry - Electrochemistry Question with Solution | TestHub

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