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ChemistryElectrochemistryConductance/conductivity/^mMedium2 minQB

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The specific conductance of a $N /10 KCl$ at $2 5^{\circ} C$ is $0.0112 ohm^{- 1} cm^{- 1}$ . The resistance of cell containing solution at the same temperature was found to be 55 ohms. The cell constant will be :

Options:

Answer:

Solution:

$K = 0.0112 Ω^{- 1} cm^{- 1}$

$R = 55Ω$

$∵ GG^{*} = K$

$\frac{1}{55} \times G_{*} = 0.0112$

$G^{*} = 0.616 cm^{- 1}$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: QB

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