Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryRelationship between Eº, DGº & KeqMedium2 minQB

ChemistryMediummultiple choice

$E_{ce ll}^{\circ} = 0.46$ V for the cell $Cu (s) + 2 Ag^{+} (aq) \to Cu^{2 +} (aq) + 2 Ag (s)$ . Which of the following expressions correctly describe the state of equilibrium in this cell?

Options:(select one or more)

Answer:

B, C

Solution:

$n = 2$ . At equilibrium $E = 0$ , so $E^{\circ} = \frac{2.303 RT}{2 F} lo g K_{c}$ : (B) true.

At 298 K, $lo g K_{c} = \frac{2 \times 0.46}{0.059} = \frac{0.92}{0.059}$ : (C) true. (A) and (D) are wrong.

Answer: (B), (C).

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Relationship between Eº, DGº & Keq

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...