Chemistry - Electrochemistry Question with Solution | TestHub

(A) ${\mathrm{BaCl}}_2+{\mathrm{Na}}_2{\mathrm{SO}}_4\to {\mathrm{BaSO}}_4\downarrow +2\mathrm{NaCl}$

Due to formation of ${\mathrm{BaSO}}_4$, conductance remains constant and then increases.

(B) $\mathrm{HCl}+{\mathrm{NaHCO}}_3\to \mathrm{NaCl}+{\mathrm{H}}_2{\mathrm{CO}}_3$

Conductance decreases due to replacement of ${\mathrm{H}}^{+}$with ${\mathrm{Na}}^{+}$ions and then increases

(C) ${\mathrm{CH}}_3\mathrm{COOH}+{\mathrm{NH}}_4\mathrm{OH}\to {\mathrm{CH}}_3{\mathrm{COONH}}_4+{\mathrm{H}}_2\mathrm{O}$

Initially conductance decreases due to replacement of ${\mathrm{OH}}^{-}$ions. But very soon, conductance increases due to formation of completely dissociated salt from undissociated ${\mathrm{NH}}_4\mathrm{OH}$

(D) $\mathrm{Ba}(\mathrm{OH}{)}_2+{\mathrm{MgSO}}_4\to \mathrm{Mg}(\mathrm{OH}{)}_2\downarrow +{\mathrm{BaSO}}_4\downarrow$

If formed products are insoluble then conductance decreases the equivalence point.