The correct order of reduction potentials of the following pairs is
A. ${Cl}_{2} / {Cl}^{-}$
B. $I_{2} / I^{-}$
C. ${Ag}^{+} / Ag$
D. ${Na}^{+} / Na$
E. ${Li}^{+} / Li$
Choose the correct answer from the options given below.

Question

The correct order of reduction potentials of the following pairs is A. Cl 2 / Cl - B. I 2 / I - C. Ag + / Ag D. Na + / Na E. Li + / Li Choose the correct answer from the options given below.

TestHub · Accepted Answer

E Cl 2 ∣ Cl − 0 = 1 .36 E ∘ I 2 ∣ I − = 0 .54 E Li + | Li = − 3 .05 E ∘ Ag + ∣ Ag = 0 .80 E Na + | Na = − 2 .71 So, we can clearly see the order of reduction potential. A > C > B > D > E

Chemistry - Electrochemistry Question with Solution | TestHub

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