Chemistry - Electrochemistry Question with Solution | TestHub

$E=E^{\circ }+0.059\log \left[{\mathrm{Ag}}^{+}\right]$. This is a straight line of positive slope with a non-zero intercept equal to the given $E^{\circ }=+0.80$ V (positive, so the line cuts the E axis above zero).

(A) has a negative slope, (B) passes through the origin ($E^{\circ }=0$) and (D) is a curve.

Answer: (C).