Chemistry - Electrochemistry Question with Solution | TestHub

For the given reactions

$S{n}^{2+}+2e^{-}\to Sn$

$S{n}^{4+}+4e^{-}\to Sn$

The electrode potentials are $E_{S{n}^{2+}/Sn}^{\circ }=0.140V$ and $E_{S{n}^{4+}/Sn}^{\circ }=0.01V$.

The value of $E_{S{n}^{4+}/S{n}^{2+}}^{\circ }$ is X × 10^-2(in V) then the value of X is . (Nearest integer).