Chemistry - Electrochemistry Question with Solution | TestHub

The overall reaction of ${\mathrm{H}}_2-{\mathrm{O}}_2$ fuel is, $2{\mathrm{H}}_2+{\mathrm{O}}_2⟶2{\mathrm{H}}_2\mathrm{O}$ Thus $4\mathrm{F}=4\times 96500\mathrm{C}$ produce water $=2\mathrm{mol}=36\mathrm{g}$ $\begin{array}{rl}\text{ Charge actually passed }& =i\times t\\ & =1\times 595.1\times 60\times 60\\ & =2142360\mathrm{C}\end{array}$ $\begin{array}{rl}& \therefore \text{ Water produced }=\frac{36}{4\times 96500}\times 2142360\\ & \cong 200\mathrm{g}\text{ or }200\mathrm{mL}\\ & \therefore \text{ Molarity of }\mathrm{NaOH}\text{ solution }=\frac{5}{40}\times \frac{1}{200}\times 1000\\ & =0.625\mathrm{M}\end{array}$