Chemistry - Electrochemistry Question with Solution | TestHub

${\mathrm{E}}_1^0\left({\mathrm{Cu}}^{+}/\mathrm{Cu}\right)=0.52\mathrm{V},{\mathrm{E}}_2^0\left({\mathrm{Cu}}^{2+}/{\mathrm{Cu}}^{+1}\right)=0.16\mathrm{V}$

The electromotive force (emf) of the couple ${\left[Cu(N{H}_3{)}_4\right]}^{2+}+2e^{-}⟶Cu+4N{H}_3$ is $E^0=-0.02V$. Calculate the dissociation constant of the complex ion ${\left[Cu(N{H}_3{)}_4\right]}^{2+}$. If the value of the dissociation constant in scientific notation is $y\times 10^{-x}$, then represent your answer as $x+y$.

Given: $\frac{2.303RT}{F}=0.06V$.