The resistance of a conductivity cell containing $0.01 MKCl$ solution at $298 K$ is $1750 Ω$ . If the conductivity of $0.01 MKCl$ solution at $298 K$
is $0.152 \times 10^{- 3} S {cm}^{- 1}$ , then the cell constant of the conductivity cell is____ $\times 10^{- 3} {cm}^{- 1}$

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For KCl solution, R = 1750 ohms Conductivity, K = 0 . 152 × 10 - 3 S cm - 1 K= l a 1 R Cell constant, l a = K XR = 0 . 152 × 10 - 3 X 1750 = 266 X 10 - 3 cm - 1

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