Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryFaraday's Law of Electrolysis/Electrolytic CellsMedium2 min

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Passage / Comprehension

1 L of aqueous solutions of CaI₂ is electrolyzed. After electrolysis the gas evolved at anode required

250 mL, 2M hypo solution (Na₂S₂O₃)

How many faradays charge passed through solution :

Answer:

Solution:

At anode : $2 I^{-} \to I_{2} + 2 e^{-}$

$I_{2} + 2 Na_{2} S_{2} O_{3} \to 2 NaI + Na_{2} S_{4} O_{6}$

Equivalent of $I_{2} =$ Equivalent hypo

moles of $I_{2} \times 2 = \frac{1}{4} \times 2 \times 1, (n_{I_{2}} = \frac{1}{4})$

For production of $\frac{1}{4}$ mole of $I_{2}, 0.5 F$ charge is required.

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Faraday's Law of Electrolysis/Electrolytic Cells

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