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ChemistryElectrochemistryConductance/conductivity/^mHard2 minPYQ_2022
ChemistryHardstatement

The solubility product of a sparingly soluble saltA2X3is1.1×10-23. If specific conductance of the solution is3×10-5Sm-1, the limiting molar conductivity of the solution isx×10-3 S m2 mol-1. The value ofxis

Answer:
3
Solution:

KspA2X3=1.1×10-23=110×10-25

Ksp=2233s5=110×10-25

4×27s5=110×10-25;  S=M=1×10-5

K=3×10-5Sm-1

λm=x×10-3Sm2 mol-1

λm=K×10-3M

=3×10-5×10-31×10-5=3×10-3Sm2 mol-1

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m
2mℹ️ Source: PYQ_2022

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