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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2022
ChemistryMediumstatement

For the given reactions

Sn2++2e-Sn

Sn4++4e-Sn the electrode potentials are ; ESn2+/Sn°=-0.140 V and ESn4+/Sn°=0.010 V. The magnitude of standard electrode potential for Sn4+/Sn2+ i.e. ESn4+/Sn2+° is____×10-2 V(Nearest integer)

Answer:
16
Solution:

(i) Sn2++2e-Sn         E10=-0.14 V

ΔG10=-2 F-0.14

(ii) Sn4++4e-Sn       E20=+0.010 VΔG20=-4F+0.010

Target Sn4++2e-Sn2+      E30=?

ΔG30=-2 FE30

Target Eq.=Eq. ii - Eq. i

-2FE30=-4F0.010--2F-0.14

E30=4×0.010+2×0.142=0.16 V=16×10-2 V

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells
2mℹ️ Source: PYQ_2022

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