The resistivity of a 0 . 8 M solution of an electrolyte is 5 × 10 - 3 Ωcm . Its molar conductivity is 10 4 Ω - 1 cm 2 mol - 1 . (Nearest integer)

Given, Resistivity ( ρ ) = 5 × 10 - 3 Ωcm Molarity ( M ) = 0 . 8 M Thus, Molar conductivity of electrolyte λ M = 1 ρ × 1000 M = 1 5 × 10 - 3 × 1000 0 . 8 = 0 . 25 × 10 6 = 25 × 10 4 cm 2 mol - 1 .

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ChemistryElectrochemistryConductance/conductivity/^mMedium2 minPYQ_2023

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The resistivity of a $0.8 M$ solution of an electrolyte is $5 \times 10^{- 3} Ωcm$ . Its molar conductivity is $10^{4} Ω^{- 1} {cm}^{2} {mol}^{- 1}$ . (Nearest integer)

Answer:

Solution:

Given,
Resistivity $(ρ) = 5 \times 10^{- 3} Ωcm$

Molarity $(M) = 0.8 M$

Thus, Molar conductivity of electrolyte $(λ_{M}) = \frac{1}{ρ} \times \frac{1000}{M}$

$= \frac{1}{5 \times 10^{- 3}} \times \frac{1000}{0.8}$

$= 0.25 \times 10^{6}$

$= 25 \times 10^{4} {cm}^{2} {mol}^{- 1}$ .

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2023

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