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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsEasy2 minPYQ_2020

ChemistryEasysingle choice

For which of these oxidation/reduction pairs will the reduction potential vary with pH?
I. $A m O_{2}^{2 +} / A m O_{2}^{+}$
II. $A m O_{2}^{2 +} / A m^{4 +}$
III. $A m^{4 +} / A m^{2 +}$

Options:

Answer:

Solution:

The half-cell reaction will be
$A m O_{2}^{+} + 4 H^{+} + 2 e^{-} \to A m^{4 +} + 2 H_{2} O$
The reaction includes $H^{+}$ ion, hence the electrode potential will depend on the pH of solution.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2020

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