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ChemistryElectrochemistryConductance/conductivity/^mMedium2 minPYQ_2012

ChemistryMediumsingle choice

The ionic conductance of $Ba^{2 +}$ and $Cl^{-}$ respectively are 127 and $76 Ω^{- 1} cm^{2}$ at infinite dilution. The equivalent conductance of $BaCl_{2}$ , at infinite dilution will be

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Answer:

Solution:

$λ_{m}^{\circ} for BaCl_{2} = λ_{m}^{\circ} Ba^{2 +} + λ_{m}^{\circ} Cl^{-} = \frac{1}{2} \times 127 + 76 = 139.5 Ω^{- 1} cm^{2}$

Stream:BITSATSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2012

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