Chemistry - Electrochemistry Question with Solution | TestHub

${\mathrm{E}}_{\mathrm{cell}}^{\circ }={\mathrm{E}}_{{\mathrm{Cu}}^{2+}\left|\mathrm{Cu}\right.}^{\circ }-{\mathrm{E}}_{{\mathrm{Zn}}^{2+}\left|\mathrm{Zn}\right.}^{\circ }=1.1\mathrm{V}$

So If $\mathrm{E}=1.1\mathrm{V}$ no electron will flow

At $\mathrm{E}>1.1 \mathrm{V}$ cell act as electrolytic cell and electron will flow from $\mathrm{Cu}$ to $\mathrm{Zn}$.

At $\mathrm{E}<1.1 \mathrm{V}$ cell act as electrochemical so $\mathrm{Zn}$ dissolve and $\mathrm{Cu}$ deposit.