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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2016

ChemistryMediumsingle choice

In the cell represented $P b_{(s)} |P b_{(1 M)}^{2 +}| |A g_{(1 M)}^{+}| A g_{(s)}$ , the reducing agent is

Answer:

Solution:

$P b_{(s)} |P b_{(1 m)}^{2 +}| |A g_{(1 m)}^{+}| A g_{(s)}$
The element losing $e^{-}$ is called the reducing agent.
$P b ⟶ P b^{2 +} + 2 e^{-}$

Stream:MHT_CETSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2016

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