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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minQB

ChemistryMediumsingle choice

The reaction, $1/2 H_{2} (g) + AgCl (s) ⟶ H^{+} (aq) + Cl^{-} (aq) + Ag (s)$ , occurs in the galvanic cell:

Answer:

Solution:

At anode: $\frac{1}{2} H_{2} (g) ⟶ H^{+} (a q .) + e^{-}$

At cathode: $A g Cl (s) + e^{-} ⟶ A g (s) + C l^{-} (a q .)$

Overall reaction: $\frac{1}{2} H_{2} (g) + A g Cl (s) ⟶ H^{+} (a q) + C l^{-} (a q) + A g (s)$ .

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: QB

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