Chemistry - Electrochemistry Question with Solution | TestHub

The rusting of iron takes place as
$2{\mathrm{H}}^{+}+2\mathrm{e}+\frac{1}{2}{\mathrm{O}}_2\to {\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right);\mathrm{E}°=+\mathrm{1.23 }\mathrm{V}$
$\mathrm{F}{\mathrm{e}}^{2+}+2\mathrm{e}\to \mathrm{F}\mathrm{e}\left(\mathrm{s}\right);\mathrm{E}°=-\mathrm{0.44 }\mathrm{V}$
Thus,$\mathrm{\Delta }\mathrm{G}°$for the net process is