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ChemistryElectrochemistryFaraday's Law of Electrolysis/Electrolytic CellsMedium2 minPYQ_2014
ChemistryMediumsingle choice

A current of 10.0 A flows for 2.00 h through an electrolytic cell containing a molten salt of metal X. This results in the decomposition of 0.250 mol of metal X at the cathode. The oxidation state of X in the molten salt is:

F=96,500 C

Options:

Answer:
C
Solution:

Quantity of Electricity  = 1 0 × 3 6 0 0 × 2 9 6 5 0 0
                                   =0.7460.75F.
If oxidation state is n+ for 1 mol deposition of a metal:
Electricity=nF (Faradays)
For 0.250 mol=0.250 nF
 0.250 nF=0.75 F
n=3

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Faraday's Law of Electrolysis/Electrolytic Cells
2mℹ️ Source: PYQ_2014

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