Chemistry - Electrochemistry Question with Solution | TestHub

Anodic half cell $\underline{\text{ Gas - gas ion electrode }}$ $\frac{1}{2}{\mathrm{H}}_{2(\mathrm{g})}\to {\mathrm{H}}_{(\mathrm{aq})}^{+}+{\mathrm{e}}^{-}$ Cathodic Reaction Metal-metal insoluble salt anion electrode ${\mathrm{Ag}}_{(\mathrm{aq})}^{+}+{\mathrm{e}}^{-}\to {\mathrm{Ag}}_{(\mathrm{s})}$ $\begin{array}{rl}& {\mathrm{AgCl}}_{(\mathrm{s})}\rightleftharpoons {\mathrm{Ag}}_{(\mathrm{aq})}^{+}+{\mathrm{Cl}}_{(\mathrm{aq})}^{-}\\ & {\mathrm{AgCl}}_{(\mathrm{s})}+{\mathrm{e}}^{-}\to {\mathrm{Ag}}_{(\mathrm{s})}+{\mathrm{Cl}}_{(\mathrm{aq})}^{-}\end{array}$ Overall redox reaction $\frac{1}{2}{\mathrm{H}}_{2(\mathrm{g})}+{\mathrm{AgCl}}_{(\mathrm{s})}\to {\mathrm{H}}_{(\mathrm{aq})}^{+}+{\mathrm{Cl}}_{(\mathrm{aq})}^{-}+{\mathrm{Ag}}_{(\mathrm{s})}$ Cell Representation Pt $\left|{\mathrm{H}}_{2(\mathrm{g})}\right|{\mathrm{kCl}}_{\text{(sol) }}\left|{\mathrm{AgCl}}_{\text{(s) }}\right|\mathrm{Ag}$