Chemistry - Electrochemistry Question with Solution | TestHub

Electrode potentials $\left({\mathrm{E}}^{\circ }\right)$ are given below : $\begin{array}{rl}& {\mathrm{Cu}}^{+}/\mathrm{Cu}=+0.52\mathrm{V},\\ & {\mathrm{Fe}}^{3+}/{\mathrm{Fe}}^{2+}=+0.77\mathrm{V},\\ & \frac{1}{2}{\mathrm{I}}_2(\mathrm{s})/{\mathrm{I}}^{-}=+0.54\mathrm{V},\\ & {\mathrm{Ag}}^{+}/\mathrm{Ag}=+0.88\mathrm{V}.\end{array}$ Based on the above potentials, strongest oxidizing agent will be :