Chemistry - Electrochemistry Question with Solution | TestHub

$\begin{array}{l}\text{ Eq. mass of }{\mathrm{Ca}}^{++}=\frac{\text{ Mol.mass }}{2}=\frac{40}{2}=20\\ \mathrm{Z}=\frac{\text{ Eq. mass of water }}{96500}=\frac{20}{96500}\\ \text{ Given }\mathrm{w}=60\mathrm{g},\mathrm{i}=5\mathrm{amp}\\ \mathrm{w}=\text{ zit }\end{array}$ $\begin{array}{l}\text{ or }60=\frac{20}{96500}\times 5\times t\\ \therefore t=\frac{96500\times 60}{20\times 5}=57900\sec =16h\end{array}$