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ChemistryElectrochemistryConductance/conductivity/^mHard2 minPYQ_2022
ChemistryHardstatement

Resistance of a conductivity cell (cell constant129 m-1) filled with74.5ppmsolution ofKClis100 Ω(labelled as solution1). When the same cell is filled withKClsolution of149ppm, the resistance is50 Ω(labelled as solution2). The ratio of molar conductivity of solution1and solution2is i.e.12=x×10-3. The value ofxis____Given, molar mass ofKClis74.5 g mol-1)

Answer:
1000
Solution:

Given lA=129 m-1

KCl solution 1:

74.5ppm,   R1=100 Ω

KCl solution 2:

149ppm,    R2=50 Ω

Here, ppm1ppm2=M1M2

and κ = 1RG*   where G* = cell constant

Since value of cell constant is same in both the cases.

k1k2 = R2R1

12=k1×1000M1k2×1000M2

=K1 K2×M2M1 = R2 R1×M2M1

=50100×14974.5 = 1

=12=1,000×10-3

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m
2mℹ️ Source: PYQ_2022

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