Chemistry - Electrochemistry Question with Solution | TestHub

The cell reaction is $$\begin{array}{l}\mathrm{Mg}+{\mathrm{Sn}}^{2+}\to {\mathrm{Mg}}^{2+}+\mathrm{Sn}\\ {\mathrm{E}}_{\text{cell }}={\mathrm{E}}_{\text{cell }}^{\circ }-\frac{0.0591}{2}\log \frac{\left[{\mathrm{Mg}}^{2+}\right]}{\left[{\mathrm{Sn}}^{2+}\right]}\\ =(2.34-0.14)-\frac{0.0591}{2}\log \frac{10^{-2}}{10^{-1}}=2.23\mathrm{V}\end{array}$$