Chemistry - Coordination Chemistry Question with Solution | TestHub

(A) O₂[AsF₆]: Contains the O₂⁺ cation (paramagnetic, one unpaired electron) and the AsF₆⁻ anion (octahedral). Thus, A $\to$ PS.

(B) NO[BF₄]: Contains the NO⁺ cation (diamagnetic, has $\pi$-bonds) and the BF₄⁻ anion (tetrahedral). Thus, B $\to$ R.

(C) PCl₅₍s₎: Exists as $[PC{l}_4{]}^{+}[PC{l}_6{]}^{-}$. The cation is tetrahedral and has no $\pi$-bonds; the anion is octahedral. Thus, C $\to$ QST.

(D) $[Cr(N{H}_3{)}_6][Co(CN{)}_6]$: Both complex ions are octahedral; the cation is paramagnetic ($C{r}^{3+}$, $d^3$). Thus, D $\to$ PST.