A hydrated isomer of CrCl 3 ⋅ 6 H 2 O , for which no geometrical isomer is possible, when 0.1 mole of such complex in 1 L solution is treated with excess of AgNO 3 , mass of white ppt. formed is

Question

A hydrated isomer of CrCl 3 ​ ⋅ 6 H 2 ​ O , for which no geometrical isomer is possible, when 0.1 mole of such complex in 1 L solution is treated with excess of AgNO 3 ​ , mass of white ppt. formed is :- (Give nearest rounded off integer)

TestHub · Accepted Answer

Identify the Isomer: The hydrate isomer of $C r C l_{3} \cdot 6 H_{2} O$ that has no geometrical isomerism and precipitates approximately $28.7 g$ of $A g Cl$ is $[C r (H_{2} O)_{5} Cl] C l_{2} \cdot H_{2} O$ (since $[C r (H_{2} O)_{4} C l_{2}]^{+}$ and $[C r (H_{2} O)_{3} C l_{3}]$ both exhibit geometrical isomerism).

Determine Ionizable Cl⁻: Each mole of $[C r (H_{2} O)_{5} Cl] C l_{2} \cdot H_{2} O$ releases $2$ moles of Cl⁻ ions outside the coordination sphere.

Calculate Moles of AgCl: For $0.1 m o l e$ of the complex, the moles of AgCl precipitated = $0.1 \times 2 = 0.2moles$ .

Calculate Mass: Using the molar mass of AgCl ( $\approx 143.5 g / m o l$ ), the mass of the precipitate is $0.2 m o l \times 143.5 g / m o l = 28.7g$ .

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