Chemistry - Coordination Chemistry Question with Solution | TestHub
ChemistryCoordination ChemistryMiscellaneous/MixedHard2 minQB
ChemistryHardsingle choice
Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code:
Column I (Complex ion) | Column II (Hybridisation, number of unpaired electrons) |
|---|---|
P. [Cr(H₂O)₆]³⁺ | 1.dsp², 1 |
Q. [Co(CN)₄]²⁻ | 2.sp³d², 5 |
R. [Ni(NH₃)₆]²⁺ | 3.d²sp³, 3 |
S. [MnF₆]⁴⁻ | 4.sp³, 4 |
| 5.sp³d², 2 |
Options:
Answer:
A
Solution:
Cr(III): d²sp³/3 unpaired; Co(CN)₄²⁻: dsp²/1; Ni(NH₃)₆²⁺: sp³d²/2; MnF₆⁴⁻: sp³d²/5. NCERT prints (ii); corrected here to (i) per Rahul’s ruling.
Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: QB
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