Chemistry - Coordination Chemistry Question with Solution | TestHub

ChemistryCoordination ChemistryMiscellaneous/MixedHard2 minQB
ChemistryHardsingle choice

Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code:

 

Column I (Complex ion)

Column II (Hybridisation, number of unpaired electrons)

P. [Cr(H₂O)₆]³⁺

1.dsp², 1

Q. [Co(CN)₄]²⁻

2.sp³d², 5

R. [Ni(NH₃)₆]²⁺

3.d²sp³, 3

S. [MnF₆]⁴⁻

4.sp³, 4

 

5.sp³d², 2

 

Options:

Answer:
A
Solution:

Cr(III): d²sp³/3 unpaired; Co(CN)₄²⁻: dsp²/1; Ni(NH₃)₆²⁺: sp³d²/2; MnF₆⁴⁻: sp³d²/5. NCERT prints (ii); corrected here to (i) per Rahul’s ruling.

Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...