In [ Co ( EDTA ) ] − 1 the number of chelates formed is x . In [ Pt ( trien ) ] 2 + the number of chelates formed is y . In [ Fe ( en ) 3 ] 2 + the number of chelates formed is z . Then, find out x

Question

In [ Co ( EDTA ) ] − 1 the number of chelates formed is x . In [ Pt ( trien ) ] 2 + the number of chelates formed is y . In [ Fe ( en ) 3 ​ ] 2 + the number of chelates formed is z . Then, find out x + z − y .

TestHub · Accepted Answer

To find the number of chelates, we determine the number of bidentate or polydentate ligands.

For $[C o (E D T A)]^{- 1}$ , EDTA is a hexadentate ligand, forming 5 chelates. So, $x = 5$ .

For $[Pt (t r i e n)]^{2 +}$ , trien (triethylenetetramine) is a tetradentate ligand, forming 3 chelates. So, $y = 3$ .

For $[F e (e n)_{3}]^{2 +}$ , en (ethylenediamine) is a bidentate ligand, forming 3 chelates. So, $z = 3$ .

Therefore, $x + z - y = 5 + 3 - 3 = 5$ .

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