Chemistry - Coordination Chemistry Question with Solution | TestHub

The relation of CFSE for tetrahedral and octahedral complex is given as
${\mathrm{\Delta }}_{\mathrm{t}}=\frac{4}{9}{\mathrm{\Delta }}_0$
So${\mathrm{\Delta }}_{\mathrm{t}}$for$[\mathrm{C}\mathrm{o}\mathrm{C}{\mathrm{l}}_4{]}^{2-}=\frac{4}{9}\times 18000\text{c}{\text{m}}^{-1}$
$=8000\text{ c}{\text{m}}^{-1}$.