Select correct about purple complex from in given paragraph :- | TestHub

Passage / Comprehension

There are many known monosubstitution products of the $[F e (CN)_{6}]^{4 -}$ ion, the most important being the red salt sodium nitrosopentacyanoferrate(II), $N a_{2} [F e (CN)_{5} NO] \cdot 2 H_{2} O$ , commonly called sodium nitroprusside.

This results from the action of nitric acid or sodium nitrite on the hexacyano complex:

$[F e (CN)_{6}]^{4 -} + 4 H^{+} + N O_{3}^{-} \to [F e (CN)_{5} NO]^{2 -} + C O_{2} + N H_{4}^{+}$

$[F e (CN)_{6}]^{4 -} + N O_{2}^{-} + H_{2} O \to [F e (CN)_{5} NO]^{2 -} + C N^{-} + 2 O H^{-}$

The anion of this compound, which is diamagnetic, contains coordinated NO with an interatomic distance of $1.13 \overset{˚}{A}$ and a stretching vibration at $1947 c m^{- 1}$ . With sulfide ion, it gives the purple anion $[F e (CN)_{5} NOS]^{4 -}$ , a reaction which forms the basis of a sensitive test for sulfide.

Select correct about purple complex from in given paragraph :-

Options:(select one or more)

Answer:

B, C, D

Solution:

The "purple complex" mentioned is the thionitroprusside anion, $[F e (CN)_{5} NOS]^{4 -}$ . Based on the chemical properties of this complex:

Oxidation State: The iron center remains in the $+ 2$ oxidation state ( $F e^{2 +}$ ).

Ligands: It contains five cyano ( $C N^{-}$ ) ligands and one thionitrosyl ( $NO S^{-}$ ) ligand formed during the sulfide test.

Correct Options: Therefore, statements (B), (C), and (D) are correct, as it features $F e^{2 +}$ , $C N^{-}$ ligands, and the $NO S^{-}$ ligand.

Chemistry - Coordination Chemistry Question with Solution | TestHub

Options:(select one or more)

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