What is the spin-only magnetic moment value (B.M.) of a divalent metal ion with atomic number 25 , in its aqueous solution?

Question

TestHub · Accepted Answer

Electronic configuration of divalent metal ion having atomic number $25$ is

Total number of unpaired electrons $= 5$

$μ$ (Magnetic moment) $= \sqrt{n (n + 2)} BM$

where $n =$ number of unpaired $e$

$∴ μ = \sqrt{5 (5 + 2)} = \sqrt{35} B . M . = 5.92 B . M .$

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