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Chemistry - Coordination Chemistry Question with Solution | TestHub

ChemistryCoordination ChemistryWerner theory + calculation of EANMedium2 minPYQ_2020

ChemistryMediumnumerical

The oxidation states of iron atoms in compounds $(A)$ , $(B)$ and $(C)$ , respectively, are $x, y$ and $z$ . Then sum of $x, y$ and $z$ is ........... $\underset{(A)}{{Na}_{4} [Fe {(CN)}_{5} (NOS)]} \underset{(B)}{{Na}_{4} [{FeO}_{4}]} \underset{(C)}{[{Fe}_{2} {(CO)}_{9}]}$

Answer:

6.00

Solution:

Oxidation state of $Fe$ in ${Na}_{4} [Fe {(CN)}_{5} (NOS)]$ :

Charge of $CN$ = $- 1$

Charge of $NOS = - 1$

Suppose oxidation state of $Fe = x$

$4 + x - 5 - 1 = 0 \Rightarrow x = + 2$

Oxidation state of $Fe in {Na}_{4} [{FeO}_{4}]$ :

$4 + x - 8 = 0 \Rightarrow x = + 4$

Oxidation state of $Fe in [{Fe}_{2} {(CO)}_{9}]$ $= 0$ because carbonyl is neutral ligand.

The oxidation states of iron in these compounds will be

$A = + 2 B = + 4 C = 0$

The sum of oxidation states will be $= 6$ .

Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:Werner theory + calculation of EAN

⏱ 2mℹ️ Source: PYQ_2020

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