Chemistry - Concentration Terms Question with Solution | TestHub

Let 1 litre solution

moles ${\mathrm{NaNO}}_3=5$

wt. ${\mathrm{NaNO}}_3=5\times 85=425\mathrm{g}$

wt. of solution $=1000\times 1.665=1665\mathrm{gm}$

Molality of ${\mathrm{BeCl}}_2=3$

$3=\frac{W/80}{(1665-425-W)}\times 1000$

$\mathrm{W}=240\mathrm{gm}$

$$\begin{array}{rl}{M}_{(BeC{l}_2)}& =\frac{240/80}{1}=3M\\ M_{Allions}& =M_{N{a}^{+}}+M_{N{O}_3^{-}}+M_{BeC{l}_2}+M_{C{l}^{-}}\\ & =5+5+3+2\times 3=19M\end{array}$$