Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termMedium2 minPYQ_2019

ChemistryMediumsingle choice

A solution of sodium sulphate contains $92 g$ of ${Na}^{+}$ ions per kilogram of water. The molality of ${Na}^{+}$ ions in that solution in $mol {kg}^{- 1}$ is:

Options:

Answer:

Solution:

Moles of $N a^{+} = \frac{W e i g h t o f N a^{+} i o n s}{M o l e c u l a r w e i g h t} = \frac{92}{23} = 4$

Molality is number of moles of solute present per Kg of Solvent

4 mole of $N a^{+}$ are present in 1 kg of water Hence, molality of $N a^{+}$ ions will be 4

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2019

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