Chemistry - Concentration Terms Question with Solution | TestHub

Let the density of solution be ' $\mathrm{d}$ ' Molarity of solution given $=3.6$ i.e. $1$ litre of solution contains $3.6$ moles of ${\mathrm{H}}_2{\mathrm{SO}}_4$ or $1$ litre of solution contains $3.6\times 98\mathrm{gms}$ of ${\mathrm{H}}_2{\mathrm{SO}}_4$ Since, the solution is $29\%$ by mass. $100\mathrm{gm}$ solution contains $29\mathrm{gm}{\mathrm{H}}_2{\mathrm{SO}}_4$ $\frac{100}{\mathrm{d}}\mathrm{ml}$ solution contains $29\mathrm{gm}$ of ${\mathrm{H}}_2{\mathrm{SO}}_4$ $1000\mathrm{ml}$ solution contains $3.6\times 98\mathrm{gm}$ of ${\mathrm{H}}_2{\mathrm{SO}}_4$ $\therefore 3.6\times 98=\frac{29\times \mathrm{d}}{100}\times 1000$ $d=1.22$ Hence, (C) is correct.