Match the List ( K = 39 , Ca = 40 ) : ( N A = 6.02 × 1 0 23 ) List - I List - II (P) 20% ( w / w ) solution of KOH (density of solution = 1.12 gm/mL) (1) 3 M (Q) Solution containing 333 gm CaCl 2

Question

Match the List ( K = 39 , Ca = 40 ) : ( N A ​ = 6.02 × 1 0 23 ) List - I List - II (P) 20% ( w / w ) solution of KOH (density of solution = 1.12 gm/mL) (1) 3 M (Q) Solution containing 333 gm CaCl 2 ​ in a 1 L solution (2) 4 M (R) Volume of 1.204 × 1 0 24 molecules of water at 4 ∘ C (3) 5 mL (S) Volume of 0.2 M NaOH solution containing 40 mg of NaOH (4) 36 mL (5) 70 mL

TestHub · Accepted Answer

(P) M = 56 10 × 20 × 1.12 ​ = 4 (Q) 333 g m C a C l 2 ​ in 1 L solution. 1 111 ​ 333 ​ = 111 333 ​ = 3 M (R) 1.204 × 1 0 24 molecules of water = 2 mole. 2 mole of water at 4℃ is 36 g m or 36 m l . (S) Volume of 0.2 MN a O H solution: 0.2 × V = 1 × 1 0 − 3 m o l e . V = 0.2 1 × 1 0 − 3 ​ × 1000 V = 5 m l

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Doubts & Discussion

List - I	List - II
(P) $20% (w / w)$ solution of KOH (density of solution = 1.12 gm/mL)	(1) 3 M
(Q) Solution containing $333 gm CaCl_{2}$ in a 1 L solution	(2) 4 M
(R) Volume of $1.204 \times 1 0^{24}$ molecules of water at $4^{\circ} C$	(3) 5 mL
(S) Volume of 0.2 M NaOH solution containing 40 mg of NaOH	(4) 36 mL
	(5) 70 mL