Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termEasy2 minPYQ_2020

ChemistryEasysingle choice

$6.02 \times 1 0^{20}$ molecules urea are present in 100 mL of its solution. The molarity of solution is

Answer:

Solution:

$n = \frac{6.02 \times 1 0^{20}}{6.02 \times 1 0^{23}} = 0.001$
$M = \frac{n}{V} \times 1000 = \frac{0.001}{100} \times 1000 = 0.01$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2020

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