Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termEasy2 minPYQ_2020

ChemistryEasyassertion reason

The mole fraction of glucose $(C_{6} H_{12} O_{6})$ in an aqueous binary solution is $0.1 .$ The mass percentage of water in it, to the nearest integer, is $\dots \dots \dots$

Answer:

Solution:

Let total mole of solution $= 1$

so mole of glucose $= 0.1$

mole of $H_{2} O = 0.9$

$% (w / w)$ of $H_{2} O = [\frac{0.9 \times 18}{0.9 \times 18 + 0.1 \times 180}] \times 100$

$= 47.368$

$= 47.37$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...