5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0 . 1 M solution ? Given : Molar Mass of Na

Question

5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0 . 1 M solution ? Given : Molar Mass of Na , O and H is 23 , 16 and 1 g mol – 1 respectively

TestHub · Accepted Answer

Molarity od stock solution = moles of solute Volume of solution in L = 5 / 40 0 . 45 M 1 V 1 = M 2 V 2 5 / 40 0 . 45 × V 1 = 0 . 1 × 500 1000 V 1 = 180 1000 = 0 . 18 L

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