29.2% ( w / w ) HCl stock solution has a density of 1.25 gmL − 1 . The molecular weight of HCl is 36.5 g mol − 1 . The volume ( mL ) of stock solution required to prepare a 200 mL solution of 0.4 M HC

Question

29.2% ( w / w ) HCl stock solution has a density of 1.25 gmL − 1 . The molecular weight of HCl is 36.5 g mol − 1 . The volume ( mL ) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is :

TestHub · Accepted Answer

Molarity of stock solution of HCl = 100 × 36.5 29.2 × 1000 × 1.25 ​ Let the volume of stock solution required = V mL Thus, V × 100 × 36.5 29.2 × 1000 × 1.25 ​ = 200 × 0.4 ⇒ V = 8 mL

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