Chemistry - Concentration Terms Question with Solution | TestHub

On mixing total vol of$\mathrm{s}\mathrm{o}\mathrm{l}\mathrm{u}\mathrm{t}\mathrm{i}\mathrm{o}\mathrm{n}=200\mathrm{ }\mathrm{m}\mathrm{l}$

$\text{M}\text{o}\text{l}\text{a}\text{r}\text{i}\text{t}\text{y}=\frac{\text{m}\text{o}\text{l}\text{a}\text{l}\text{i}\text{t}\text{y}\times \text{d}\times 1000}{\left(\text{m}\text{o}\text{l}\text{a}\text{l}\text{i}\text{t}\text{y}\times {\text{M}}^{\prime }+1000\right)}$
or
$\frac{1}{\text{M}\text{o}\text{l}\text{a}\text{r}\text{i}\text{t}\text{y}}=\frac{1}{\text{d}}\left(\frac{1}{\text{m}\text{o}\text{l}\text{a}\text{l}\text{i}\text{t}\text{y}}+\frac{{\text{M}}^{\prime }}{1000}\right)$
Let molarity of$5\text{ m}{\text{H}}_2{\text{SO}}_4={\text{M}}_1$

$\frac{1}{{\mathrm{M}}_1}=\frac{1}{\mathrm{d}}\left(\frac{1}{\mathrm{m}}+\frac{\mathrm{M}\mathrm{\prime }}{1000}\right)$

Where$\mathrm{M}\mathrm{\prime }=\mathrm{m}\mathrm{o}\mathrm{l}$wt. of${\mathrm{H}}_2{\mathrm{S}\mathrm{O}}_4$

$\frac{1}{{\mathrm{M}}_1}=\frac{1}{1}\left(\frac{1}{5}+\frac{98}{1000}\right)=0.298\simeq 0.3$

${\mathrm{M}}_1=10/3$

Let molarity of$8\text{m}{\text{H}}_2{\text{SO}}_4={\text{M}}_2$

$\frac{1}{{\mathrm{M}}_2}=\frac{1}{1.25}\left(\frac{1}{8}+\frac{\mathrm{M}\mathrm{\prime }}{1000}\right)$

$=\frac{1}{1.25}\times \left(\frac{1}{8}+\frac{98}{1000}\right)$

or$\frac{1}{{\mathrm{M}}_2}=\frac{1}{1.25}\mathrm{ }\times \mathrm{ }0.223$

or${\text{M}}_2=\frac{1.25}{0.223}=5.6\text{M}$

${\text{M}}_{\text{mix}\text{.}}=\frac{{\text{M}}_{\text{1}}{\text{V}}_1+{\text{M}}_{\text{2}}{\text{V}}_2}{{\text{V}}_{\text{1}}{\text{+V}}_{\text{2}}}$$=4.5\text{ M}$